Base | Representation |
---|---|
bin | 1001000110001010001… |
… | …01111001000101100011 |
3 | 1002212201202020120021002 |
4 | 10203011011321011203 |
5 | 20110042320121121 |
6 | 355325245022215 |
7 | 31403065504556 |
oct | 4430505710543 |
9 | 1085652216232 |
10 | 312544301411 |
11 | 110605123651 |
12 | 506a655496b |
13 | 2361b989b74 |
14 | 111ad16869d |
15 | 81e3ae8e0b |
hex | 48c5179163 |
312544301411 has 2 divisors, whose sum is σ = 312544301412. Its totient is φ = 312544301410.
The previous prime is 312544301393. The next prime is 312544301413. The reversal of 312544301411 is 114103445213.
It is a strong prime.
It is an emirp because it is prime and its reverse (114103445213) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312544301411 is a prime.
It is a Sophie Germain prime.
Together with 312544301413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (312544301413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156272150705 + 156272150706.
It is an arithmetic number, because the mean of its divisors is an integer number (156272150706).
Almost surely, 2312544301411 is an apocalyptic number.
312544301411 is a deficient number, since it is larger than the sum of its proper divisors (1).
312544301411 is an equidigital number, since it uses as much as digits as its factorization.
312544301411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 312544301411 its reverse (114103445213), we get a palindrome (426647746624).
The spelling of 312544301411 in words is "three hundred twelve billion, five hundred forty-four million, three hundred one thousand, four hundred eleven".
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