3125483117 has 2 divisors, whose sum is σ = 3125483118. Its totient is φ = 3125483116.

The previous prime is 3125483069. The next prime is 3125483171. The reversal of 3125483117 is 7113845213.

Together with next prime (3125483171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2375490121 + 749992996 = 48739^2 + 27386^2 .

It is a cyclic number.

It is not a de Polignac number, because 3125483117 - 2¹⁴ = 3125466733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3125483197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562741558 + 1562741559.

It is an arithmetic number, because the mean of its divisors is an integer number (1562741559).

Almost surely, 2^3125483117 is an apocalyptic number.

It is an amenable number.

3125483117 is a deficient number, since it is larger than the sum of its proper divisors (1).

3125483117 is an equidigital number, since it uses as much as digits as its factorization.

3125483117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 20160, while the sum is 35.

The square root of 3125483117 is about 55906.0204003111. The cubic root of 3125483117 is about 1462.0842061671.

The spelling of 3125483117 in words is "three billion, one hundred twenty-five million, four hundred eighty-three thousand, one hundred seventeen".