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312660543451913 is a prime number
BaseRepresentation
bin100011100010111001111010…
…0101000001011001100001001
31112000001001111212001202202122
41013011303310220023030021
5311440112243110430123
63024550134252541025
7122566656510265166
oct10705636450131411
91460031455052678
10312660543451913
119069465680a398
122b09785b481775
131055c9bb968c57
14572cbcb3b506d
1526230418ecbc8
hex11c5cf4a0b309

312660543451913 has 2 divisors, whose sum is σ = 312660543451914. Its totient is φ = 312660543451912.

The previous prime is 312660543451903. The next prime is 312660543452003. The reversal of 312660543451913 is 319154345066213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 231211579043449 + 81448964408464 = 15205643^2 + 9024908^2 .

It is a cyclic number.

It is not a de Polignac number, because 312660543451913 - 216 = 312660543386377 is a prime.

It is a super-3 number, since 3×3126605434519133 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (312660543451903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156330271725956 + 156330271725957.

It is an arithmetic number, because the mean of its divisors is an integer number (156330271725957).

Almost surely, 2312660543451913 is an apocalyptic number.

It is an amenable number.

312660543451913 is a deficient number, since it is larger than the sum of its proper divisors (1).

312660543451913 is an equidigital number, since it uses as much as digits as its factorization.

312660543451913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6998400, while the sum is 53.

The spelling of 312660543451913 in words is "three hundred twelve trillion, six hundred sixty billion, five hundred forty-three million, four hundred fifty-one thousand, nine hundred thirteen".