Base | Representation |
---|---|
bin | 101101100001111000011… |
… | …001011101101000110111 |
3 | 102002002212101122111111211 |
4 | 231201320121131220313 |
5 | 402230143032214112 |
6 | 10353155234142251 |
7 | 442021331216233 |
oct | 55417031355067 |
9 | 12062771574454 |
10 | 3128756132407 |
11 | aa69972a7764 |
12 | 42645a121987 |
13 | 19906aac11b9 |
14 | ab60b0d35c3 |
15 | 565bd2a40a7 |
hex | 2d87865da37 |
3128756132407 has 2 divisors, whose sum is σ = 3128756132408. Its totient is φ = 3128756132406.
The previous prime is 3128756132371. The next prime is 3128756132459. The reversal of 3128756132407 is 7042316578213.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3128756132407 is a prime.
It is a super-2 number, since 2×31287561324072 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3128756132497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1564378066203 + 1564378066204.
It is an arithmetic number, because the mean of its divisors is an integer number (1564378066204).
Almost surely, 23128756132407 is an apocalyptic number.
3128756132407 is a deficient number, since it is larger than the sum of its proper divisors (1).
3128756132407 is an equidigital number, since it uses as much as digits as its factorization.
3128756132407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1693440, while the sum is 49.
The spelling of 3128756132407 in words is "three trillion, one hundred twenty-eight billion, seven hundred fifty-six million, one hundred thirty-two thousand, four hundred seven".
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