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313000341240130 = 2531300034124013
BaseRepresentation
bin100011100101011000001001…
…0001001110111100101000010
31112001020112120221112220120221
41013022300102021313211002
5312011144144324141010
63025410212142453254
7122633346145652605
oct10712602211674502
91461215527486527
10313000341240130
1190805776800a55
122b131690b9422a
1310585a6199a16b
145741423cc833c
15262bccce4ddda
hex11cac12277942

313000341240130 has 8 divisors (see below), whose sum is σ = 563400614232252. Its totient is φ = 125200136496048.

The previous prime is 313000341240091. The next prime is 313000341240131. The reversal of 313000341240130 is 31042143000313.

It can be written as a sum of positive squares in 2 ways, for example, as 292894506733921 + 20105834506209 = 17114161^2 + 4483953^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 313000341240095 and 313000341240104.

It is not an unprimeable number, because it can be changed into a prime (313000341240131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15650017061997 + ... + 15650017062016.

Almost surely, 2313000341240130 is an apocalyptic number.

313000341240130 is a deficient number, since it is larger than the sum of its proper divisors (250400272992122).

313000341240130 is a wasteful number, since it uses less digits than its factorization.

313000341240130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31300034124020.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 313000341240130 its reverse (31042143000313), we get a palindrome (344042484240443).

The spelling of 313000341240130 in words is "three hundred thirteen trillion, three hundred forty-one million, two hundred forty thousand, one hundred thirty".

Divisors: 1 2 5 10 31300034124013 62600068248026 156500170620065 313000341240130