Base | Representation |
---|---|
bin | 1001000111000000101… |
… | …00011111001000100111 |
3 | 1002220220120210221201121 |
4 | 10203200110133020213 |
5 | 20112011241041403 |
6 | 355442444034411 |
7 | 31420313361301 |
oct | 4434024371047 |
9 | 1086816727647 |
10 | 313001112103 |
11 | 110819a71249 |
12 | 507b3532a07 |
13 | 236924cc854 |
14 | 11213aba971 |
15 | 821dc803bd |
hex | 48e051f227 |
313001112103 has 2 divisors, whose sum is σ = 313001112104. Its totient is φ = 313001112102.
The previous prime is 313001112071. The next prime is 313001112107. The reversal of 313001112103 is 301211100313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313001112103 - 25 = 313001112071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313001112107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156500556051 + 156500556052.
It is an arithmetic number, because the mean of its divisors is an integer number (156500556052).
Almost surely, 2313001112103 is an apocalyptic number.
313001112103 is a deficient number, since it is larger than the sum of its proper divisors (1).
313001112103 is an equidigital number, since it uses as much as digits as its factorization.
313001112103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 313001112103 its reverse (301211100313), we get a palindrome (614212212416).
It can be divided in two parts, 313001 and 112103, that added together give a square (425104 = 6522).
The spelling of 313001112103 in words is "three hundred thirteen billion, one million, one hundred twelve thousand, one hundred three".
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