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313001112103 is a prime number
BaseRepresentation
bin1001000111000000101…
…00011111001000100111
31002220220120210221201121
410203200110133020213
520112011241041403
6355442444034411
731420313361301
oct4434024371047
91086816727647
10313001112103
11110819a71249
12507b3532a07
13236924cc854
1411213aba971
15821dc803bd
hex48e051f227

313001112103 has 2 divisors, whose sum is σ = 313001112104. Its totient is φ = 313001112102.

The previous prime is 313001112071. The next prime is 313001112107. The reversal of 313001112103 is 301211100313.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 313001112103 - 25 = 313001112071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313001112107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156500556051 + 156500556052.

It is an arithmetic number, because the mean of its divisors is an integer number (156500556052).

Almost surely, 2313001112103 is an apocalyptic number.

313001112103 is a deficient number, since it is larger than the sum of its proper divisors (1).

313001112103 is an equidigital number, since it uses as much as digits as its factorization.

313001112103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 313001112103 its reverse (301211100313), we get a palindrome (614212212416).

It can be divided in two parts, 313001 and 112103, that added together give a square (425104 = 6522).

The spelling of 313001112103 in words is "three hundred thirteen billion, one million, one hundred twelve thousand, one hundred three".