Base | Representation |
---|---|
bin | 101101100011000011110… |
… | …011011011101000101111 |
3 | 102002020010120011011201212 |
4 | 231203003303123220233 |
5 | 402240240413344101 |
6 | 10353524545425035 |
7 | 442064562325613 |
oct | 55430363335057 |
9 | 12066116134655 |
10 | 3130021231151 |
11 | aa7486427111 |
12 | 42675193b17b |
13 | 19920cc29339 |
14 | ab6cb12b343 |
15 | 5664439d1bb |
hex | 2d8c3cdba2f |
3130021231151 has 2 divisors, whose sum is σ = 3130021231152. Its totient is φ = 3130021231150.
The previous prime is 3130021231123. The next prime is 3130021231163. The reversal of 3130021231151 is 1511321200313.
It is a strong prime.
It is an emirp because it is prime and its reverse (1511321200313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3130021231151 - 218 = 3130020969007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3130021231111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565010615575 + 1565010615576.
It is an arithmetic number, because the mean of its divisors is an integer number (1565010615576).
Almost surely, 23130021231151 is an apocalyptic number.
3130021231151 is a deficient number, since it is larger than the sum of its proper divisors (1).
3130021231151 is an equidigital number, since it uses as much as digits as its factorization.
3130021231151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 3130021231151 its reverse (1511321200313), we get a palindrome (4641342431464).
The spelling of 3130021231151 in words is "three trillion, one hundred thirty billion, twenty-one million, two hundred thirty-one thousand, one hundred fifty-one".
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