Base | Representation |
---|---|
bin | 1110001110111101011000… |
… | …11101001000000001000101 |
3 | 11002211021121010012000002112 |
4 | 13013132230131020001011 |
5 | 13100311023410031432 |
6 | 150323100221350405 |
7 | 6410242052135435 |
oct | 707365435100105 |
9 | 132737533160075 |
10 | 31300320002117 |
11 | 9a78433709601 |
12 | 3616265a08405 |
13 | 14607b891884a |
14 | 7a2d2d2342c5 |
15 | 3942d6d5e7b2 |
hex | 1c77ac748045 |
31300320002117 has 2 divisors, whose sum is σ = 31300320002118. Its totient is φ = 31300320002116.
The previous prime is 31300320002099. The next prime is 31300320002183. The reversal of 31300320002117 is 71120002300313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22550047218721 + 8750272783396 = 4748689^2 + 2958086^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31300320002117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31300320002092 and 31300320002101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31300320002197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15650160001058 + 15650160001059.
It is an arithmetic number, because the mean of its divisors is an integer number (15650160001059).
Almost surely, 231300320002117 is an apocalyptic number.
It is an amenable number.
31300320002117 is a deficient number, since it is larger than the sum of its proper divisors (1).
31300320002117 is an equidigital number, since it uses as much as digits as its factorization.
31300320002117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 756, while the sum is 23.
The spelling of 31300320002117 in words is "thirty-one trillion, three hundred billion, three hundred twenty million, two thousand, one hundred seventeen".
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