313005532425241 has 2 divisors, whose sum is σ = 313005532425242. Its totient is φ = 313005532425240.

The previous prime is 313005532425239. The next prime is 313005532425251. The reversal of 313005532425241 is 142524235500313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 310698049903641 + 2307482521600 = 17626629^2 + 1519040^2 .

It is a cyclic number.

It is not a de Polignac number, because 313005532425241 - 2¹ = 313005532425239 is a prime.

Together with 313005532425239, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 313005532425194 and 313005532425203.

It is not a weakly prime, because it can be changed into another prime (313005532425251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156502766212620 + 156502766212621.

It is an arithmetic number, because the mean of its divisors is an integer number (156502766212621).

Almost surely, 2^{313005532425241} is an apocalyptic number.

It is an amenable number.

313005532425241 is a deficient number, since it is larger than the sum of its proper divisors (1).

313005532425241 is an equidigital number, since it uses as much as digits as its factorization.

313005532425241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 313005532425241 its reverse (142524235500313), we get a palindrome (455529767925554).

The spelling of 313005532425241 in words is "three hundred thirteen trillion, five billion, five hundred thirty-two million, four hundred twenty-five thousand, two hundred forty-one".