Base | Representation |
---|---|
bin | 101101100011001111101… |
… | …101101001011001100011 |
3 | 102002020122111010120122221 |
4 | 231203033231221121203 |
5 | 402241143041310001 |
6 | 10354000444211511 |
7 | 442102536562423 |
oct | 55431755513143 |
9 | 12066574116587 |
10 | 3130221041251 |
11 | aa757919a427 |
12 | 4267a8839b97 |
13 | 199242448075 |
14 | ab7098a0483 |
15 | 56656bbb1a1 |
hex | 2d8cfb69663 |
3130221041251 has 2 divisors, whose sum is σ = 3130221041252. Its totient is φ = 3130221041250.
The previous prime is 3130221041191. The next prime is 3130221041317. The reversal of 3130221041251 is 1521401220313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3130221041251 - 213 = 3130221033059 is a prime.
It is not a weakly prime, because it can be changed into another prime (3130221011251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565110520625 + 1565110520626.
It is an arithmetic number, because the mean of its divisors is an integer number (1565110520626).
Almost surely, 23130221041251 is an apocalyptic number.
3130221041251 is a deficient number, since it is larger than the sum of its proper divisors (1).
3130221041251 is an equidigital number, since it uses as much as digits as its factorization.
3130221041251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 3130221041251 its reverse (1521401220313), we get a palindrome (4651622261564).
The spelling of 3130221041251 in words is "three trillion, one hundred thirty billion, two hundred twenty-one million, forty-one thousand, two hundred fifty-one".
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