Base | Representation |
---|---|
bin | 1001000111000011011… |
… | …00010011010000001111 |
3 | 1002220222012010111020111 |
4 | 10203201230103100033 |
5 | 20112033134211421 |
6 | 355445025300451 |
7 | 31421013136105 |
oct | 4434154232017 |
9 | 1086865114214 |
10 | 313024132111 |
11 | 110830a64549 |
12 | 507bb194727 |
13 | 236971cc762 |
14 | 11216b8dc75 |
15 | 8220ccaee1 |
hex | 48e1b1340f |
313024132111 has 2 divisors, whose sum is σ = 313024132112. Its totient is φ = 313024132110.
The previous prime is 313024132087. The next prime is 313024132129. The reversal of 313024132111 is 111231420313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313024132111 - 219 = 313023607823 is a prime.
It is a super-3 number, since 3×3130241321113 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313024132151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156512066055 + 156512066056.
It is an arithmetic number, because the mean of its divisors is an integer number (156512066056).
Almost surely, 2313024132111 is an apocalyptic number.
313024132111 is a deficient number, since it is larger than the sum of its proper divisors (1).
313024132111 is an equidigital number, since it uses as much as digits as its factorization.
313024132111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 313024132111 its reverse (111231420313), we get a palindrome (424255552424).
The spelling of 313024132111 in words is "three hundred thirteen billion, twenty-four million, one hundred thirty-two thousand, one hundred eleven".
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