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313031322119939 is a prime number
BaseRepresentation
bin100011100101100110100100…
…0110000100010111100000011
31112001100111120001112200002212
41013023031020300202330003
5312012201121430314224
63025432334254332335
7122635523656046423
oct10713151060427403
91461314501480085
10313031322119939
1190817924699555
122b1376984ba0ab
131058895b3365c7
145742b22704483
15262c9e2c2dd0e
hex11cb348c22f03

313031322119939 has 2 divisors, whose sum is σ = 313031322119940. Its totient is φ = 313031322119938.

The previous prime is 313031322119897. The next prime is 313031322119941. The reversal of 313031322119939 is 939911223130313.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 313031322119939 - 228 = 313031053684483 is a prime.

It is a super-3 number, since 3×3130313221199393 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 313031322119941, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (313031322119839) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156515661059969 + 156515661059970.

It is an arithmetic number, because the mean of its divisors is an integer number (156515661059970).

Almost surely, 2313031322119939 is an apocalyptic number.

313031322119939 is a deficient number, since it is larger than the sum of its proper divisors (1).

313031322119939 is an equidigital number, since it uses as much as digits as its factorization.

313031322119939 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 708588, while the sum is 50.

The spelling of 313031322119939 in words is "three hundred thirteen trillion, thirty-one billion, three hundred twenty-two million, one hundred nineteen thousand, nine hundred thirty-nine".