Base | Representation |
---|---|
bin | 11101001001110111… |
… | …010101011001100101 |
3 | 2222210122000122111012 |
4 | 131021313111121211 |
5 | 1003102311412123 |
6 | 22214133352005 |
7 | 2155512503141 |
oct | 351167253145 |
9 | 88718018435 |
10 | 31304013413 |
11 | 12304332672 |
12 | 6097798605 |
13 | 2c4b5a6a7a |
14 | 172d6d2221 |
15 | c3335d378 |
hex | 749dd5665 |
31304013413 has 2 divisors, whose sum is σ = 31304013414. Its totient is φ = 31304013412.
The previous prime is 31304013359. The next prime is 31304013463. The reversal of 31304013413 is 31431040313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31303163329 + 850084 = 176927^2 + 922^2 .
It is a cyclic number.
It is not a de Polignac number, because 31304013413 - 28 = 31304013157 is a prime.
It is a super-2 number, since 2×313040134132 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31304013463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15652006706 + 15652006707.
It is an arithmetic number, because the mean of its divisors is an integer number (15652006707).
Almost surely, 231304013413 is an apocalyptic number.
It is an amenable number.
31304013413 is a deficient number, since it is larger than the sum of its proper divisors (1).
31304013413 is an equidigital number, since it uses as much as digits as its factorization.
31304013413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 31304013413 its reverse (31431040313), we get a palindrome (62735053726).
The spelling of 31304013413 in words is "thirty-one billion, three hundred four million, thirteen thousand, four hundred thirteen".
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