Base | Representation |
---|---|
bin | 1001000111000101010… |
… | …10000110010011011101 |
3 | 1002221000022121112022021 |
4 | 10203202222012103131 |
5 | 20112101311110442 |
6 | 355450404420141 |
7 | 31421300630101 |
oct | 4434252062335 |
9 | 1087008545267 |
10 | 313040331997 |
11 | 11083a119788 |
12 | 508046a7651 |
13 | 2369a6822a3 |
14 | 11218da9901 |
15 | 822242ae67 |
hex | 48e2a864dd |
313040331997 has 2 divisors, whose sum is σ = 313040331998. Its totient is φ = 313040331996.
The previous prime is 313040331973. The next prime is 313040332013. The reversal of 313040331997 is 799133040313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 245118068836 + 67922263161 = 495094^2 + 260619^2 .
It is an emirp because it is prime and its reverse (799133040313) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313040331997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313040331697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156520165998 + 156520165999.
It is an arithmetic number, because the mean of its divisors is an integer number (156520165999).
Almost surely, 2313040331997 is an apocalyptic number.
It is an amenable number.
313040331997 is a deficient number, since it is larger than the sum of its proper divisors (1).
313040331997 is an equidigital number, since it uses as much as digits as its factorization.
313040331997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 183708, while the sum is 43.
The spelling of 313040331997 in words is "three hundred thirteen billion, forty million, three hundred thirty-one thousand, nine hundred ninety-seven".
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