Base | Representation |
---|---|
bin | 101101100011011011110… |
… | …001101101101100000101 |
3 | 102002021011120222012022021 |
4 | 231203123301231230011 |
5 | 402242101344341424 |
6 | 10354032514203141 |
7 | 442110545103625 |
oct | 55433361555405 |
9 | 12067146865267 |
10 | 3130423433989 |
11 | aa7672467055 |
12 | 4268445834b1 |
13 | 19927535c497 |
14 | ab728706885 |
15 | 566698494e4 |
hex | 2d8dbc6db05 |
3130423433989 has 2 divisors, whose sum is σ = 3130423433990. Its totient is φ = 3130423433988.
The previous prime is 3130423433941. The next prime is 3130423434013. The reversal of 3130423433989 is 9893343240313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1898250172900 + 1232173261089 = 1377770^2 + 1110033^2 .
It is a cyclic number.
It is not a de Polignac number, because 3130423433989 - 237 = 2992984480517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3130423433909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565211716994 + 1565211716995.
It is an arithmetic number, because the mean of its divisors is an integer number (1565211716995).
Almost surely, 23130423433989 is an apocalyptic number.
It is an amenable number.
3130423433989 is a deficient number, since it is larger than the sum of its proper divisors (1).
3130423433989 is an equidigital number, since it uses as much as digits as its factorization.
3130423433989 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5038848, while the sum is 52.
The spelling of 3130423433989 in words is "three trillion, one hundred thirty billion, four hundred twenty-three million, four hundred thirty-three thousand, nine hundred eighty-nine".
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