Base | Representation |
---|---|
bin | 100011100101101100001100… |
… | …1011111110010100001001010 |
3 | 1112001101122202202201220102210 |
4 | 1013023120121133302201022 |
5 | 312012400403002200132 |
6 | 3025442054211405550 |
7 | 122636432425143633 |
oct | 10713303137624112 |
9 | 1461348682656383 |
10 | 313043414100042 |
11 | 90821a6a26413a |
12 | 2b139ab1bb38b6 |
13 | 10589b37564412 |
14 | 574354c62688a |
15 | 262ce9e5bcbcc |
hex | 11cb6197f284a |
313043414100042 has 16 divisors (see below), whose sum is σ = 627617602846080. Its totient is φ = 104092675592352.
The previous prime is 313043414099993. The next prime is 313043414100101. The reversal of 313043414100042 is 240001414340313.
It is a super-3 number, since 3×3130434141000423 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 313043414099982 and 313043414100009.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63782274258 + ... + 63782279165.
It is an arithmetic number, because the mean of its divisors is an integer number (39226100177880).
Almost surely, 2313043414100042 is an apocalyptic number.
313043414100042 is an abundant number, since it is smaller than the sum of its proper divisors (314574188746038).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
313043414100042 is a wasteful number, since it uses less digits than its factorization.
313043414100042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127564553837.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 313043414100042 its reverse (240001414340313), we get a palindrome (553044828440355).
The spelling of 313043414100042 in words is "three hundred thirteen trillion, forty-three billion, four hundred fourteen million, one hundred thousand, forty-two".
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