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3130544335132 = 224644716850089
BaseRepresentation
bin101101100011100010111…
…110111010100100011100
3102002021111000110121111101
4231203202332322210130
5402242323322211012
610354052513402444
7442113543540244
oct55434276724434
912067430417441
103130544335132
11aa7724733955
12426878b69424
13199294410616
14ab73a7b8b24
155667527bd57
hex2d8e2fba91c

3130544335132 has 12 divisors (see below), whose sum is σ = 5478570862240. Its totient is φ = 1565238374496.

The previous prime is 3130544335117. The next prime is 3130544335147. The reversal of 3130544335132 is 2315334450313.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (3130544335117) and next prime (3130544335147).

It is a junction number, because it is equal to n+sod(n) for n = 3130544335091 and 3130544335100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8239257 + ... + 8610832.

Almost surely, 23130544335132 is an apocalyptic number.

It is an amenable number.

3130544335132 is a deficient number, since it is larger than the sum of its proper divisors (2348026527108).

3130544335132 is a wasteful number, since it uses less digits than its factorization.

3130544335132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16896540 (or 16896538 counting only the distinct ones).

The product of its (nonzero) digits is 194400, while the sum is 37.

Adding to 3130544335132 its reverse (2315334450313), we get a palindrome (5445878785445).

The spelling of 3130544335132 in words is "three trillion, one hundred thirty billion, five hundred forty-four million, three hundred thirty-five thousand, one hundred thirty-two".

Divisors: 1 2 4 46447 92894 185788 16850089 33700178 67400356 782636083783 1565272167566 3130544335132