Base | Representation |
---|---|
bin | 100011100110001100001100… |
… | …0001110010101001101111111 |
3 | 1112001122020002110101010212222 |
4 | 1013030120120032111031333 |
5 | 312020012101212114403 |
6 | 3025533415114515555 |
7 | 122644414013434664 |
oct | 10714303016251577 |
9 | 1461566073333788 |
10 | 313112112223103 |
11 | 90849112596856 |
12 | 2b14b284a35bbb |
13 | 1059346506768b |
14 | 57469c838da6b |
15 | 262eb7076c338 |
hex | 11cc61839537f |
313112112223103 has 2 divisors, whose sum is σ = 313112112223104. Its totient is φ = 313112112223102.
The previous prime is 313112112223067. The next prime is 313112112223117. The reversal of 313112112223103 is 301322211211313.
It is a strong prime.
It is an emirp because it is prime and its reverse (301322211211313) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313112112223103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313112112223153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156556056111551 + 156556056111552.
It is an arithmetic number, because the mean of its divisors is an integer number (156556056111552).
Almost surely, 2313112112223103 is an apocalyptic number.
313112112223103 is a deficient number, since it is larger than the sum of its proper divisors (1).
313112112223103 is an equidigital number, since it uses as much as digits as its factorization.
313112112223103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 313112112223103 its reverse (301322211211313), we get a palindrome (614434323434416).
The spelling of 313112112223103 in words is "three hundred thirteen trillion, one hundred twelve billion, one hundred twelve million, two hundred twenty-three thousand, one hundred three".
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