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31312103117 is a prime number
BaseRepresentation
bin11101001010010110…
…001100011011001101
32222211012020122110212
4131022112030123031
51003111344244432
622215023012205
72155641325241
oct351226143315
988735218425
1031312103117
1112308958579
12609a43a065
132c50179c89
1417307da421
15c33e0a2b2
hex74a58c6cd

31312103117 has 2 divisors, whose sum is σ = 31312103118. Its totient is φ = 31312103116.

The previous prime is 31312103083. The next prime is 31312103143. The reversal of 31312103117 is 71130121313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22173890281 + 9138212836 = 148909^2 + 95594^2 .

It is an emirp because it is prime and its reverse (71130121313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31312103117 - 210 = 31312102093 is a prime.

It is a super-2 number, since 2×313121031172 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31312103092 and 31312103101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31312103917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656051558 + 15656051559.

It is an arithmetic number, because the mean of its divisors is an integer number (15656051559).

Almost surely, 231312103117 is an apocalyptic number.

It is an amenable number.

31312103117 is a deficient number, since it is larger than the sum of its proper divisors (1).

31312103117 is an equidigital number, since it uses as much as digits as its factorization.

31312103117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 23.

The spelling of 31312103117 in words is "thirty-one billion, three hundred twelve million, one hundred three thousand, one hundred seventeen".