Base | Representation |
---|---|
bin | 101101100100001100101… |
… | …101101010100010110001 |
3 | 102002100021210212102221002 |
4 | 231210030231222202301 |
5 | 402300242040043423 |
6 | 10354250203411345 |
7 | 442140104504264 |
oct | 55441455524261 |
9 | 12070253772832 |
10 | 3131244456113 |
11 | aa7a53956134 |
12 | 426a33523b55 |
13 | 199376492aa7 |
14 | ab7a5784cdb |
15 | 566b6975228 |
hex | 2d90cb6a8b1 |
3131244456113 has 2 divisors, whose sum is σ = 3131244456114. Its totient is φ = 3131244456112.
The previous prime is 3131244456089. The next prime is 3131244456149. The reversal of 3131244456113 is 3116544421313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3109413802609 + 21830653504 = 1763353^2 + 147752^2 .
It is a cyclic number.
It is not a de Polignac number, because 3131244456113 - 224 = 3131227678897 is a prime.
It is not a weakly prime, because it can be changed into another prime (3131246456113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565622228056 + 1565622228057.
It is an arithmetic number, because the mean of its divisors is an integer number (1565622228057).
Almost surely, 23131244456113 is an apocalyptic number.
It is an amenable number.
3131244456113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3131244456113 is an equidigital number, since it uses as much as digits as its factorization.
3131244456113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 38.
Adding to 3131244456113 its reverse (3116544421313), we get a palindrome (6247788877426).
The spelling of 3131244456113 in words is "three trillion, one hundred thirty-one billion, two hundred forty-four million, four hundred fifty-six thousand, one hundred thirteen".
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