Base | Representation |
---|---|
bin | 100011100110010100111111… |
… | …1110111101111100011001101 |
3 | 1112001201000220221101122122111 |
4 | 1013030221333313233203031 |
5 | 312020314322414020133 |
6 | 3025550224301544021 |
7 | 122645653566415501 |
oct | 10714517767574315 |
9 | 1461630827348574 |
10 | 313131031001293 |
11 | 9085614076692a |
12 | 2b152a84875011 |
13 | 1059518b73789b |
14 | 57478a0c24301 |
15 | 26303cb6111cd |
hex | 11cca7fdef8cd |
313131031001293 has 2 divisors, whose sum is σ = 313131031001294. Its totient is φ = 313131031001292.
The previous prime is 313131031001249. The next prime is 313131031001311. The reversal of 313131031001293 is 392100130131313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 304908801643044 + 8222229358249 = 17461638^2 + 2867443^2 .
It is a cyclic number.
It is not a de Polignac number, because 313131031001293 - 217 = 313131030870221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313131031001693) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156565515500646 + 156565515500647.
It is an arithmetic number, because the mean of its divisors is an integer number (156565515500647).
Almost surely, 2313131031001293 is an apocalyptic number.
It is an amenable number.
313131031001293 is a deficient number, since it is larger than the sum of its proper divisors (1).
313131031001293 is an equidigital number, since it uses as much as digits as its factorization.
313131031001293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4374, while the sum is 31.
The spelling of 313131031001293 in words is "three hundred thirteen trillion, one hundred thirty-one billion, thirty-one million, one thousand, two hundred ninety-three".
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