Base | Representation |
---|---|
bin | 101101100100010001110… |
… | …100110101100000110011 |
3 | 102002100111210020210210021 |
4 | 231210101310311200303 |
5 | 402300431014102011 |
6 | 10354302505544311 |
7 | 442142165504056 |
oct | 55442164654063 |
9 | 12070453223707 |
10 | 3131330222131 |
11 | aa7a98305441 |
12 | 426a581a5097 |
13 | 19938b191807 |
14 | ab7b2d0ca9d |
15 | 566be267471 |
hex | 2d911d35833 |
3131330222131 has 2 divisors, whose sum is σ = 3131330222132. Its totient is φ = 3131330222130.
The previous prime is 3131330222093. The next prime is 3131330222147. The reversal of 3131330222131 is 1312220331313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3131330222131 - 215 = 3131330189363 is a prime.
It is a super-2 number, since 2×31313302221312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3131330222096 and 3131330222105.
It is not a weakly prime, because it can be changed into another prime (3131330222431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565665111065 + 1565665111066.
It is an arithmetic number, because the mean of its divisors is an integer number (1565665111066).
Almost surely, 23131330222131 is an apocalyptic number.
3131330222131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3131330222131 is an equidigital number, since it uses as much as digits as its factorization.
3131330222131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 3131330222131 its reverse (1312220331313), we get a palindrome (4443550553444).
The spelling of 3131330222131 in words is "three trillion, one hundred thirty-one billion, three hundred thirty million, two hundred twenty-two thousand, one hundred thirty-one".
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