Base | Representation |
---|---|
bin | 1110001111010101110010… |
… | …11011010100100110000111 |
3 | 11002212112102020220122021221 |
4 | 13013222321123110212013 |
5 | 13101014342132110142 |
6 | 150333104314221211 |
7 | 6411214541625052 |
oct | 707527133244607 |
9 | 132775366818257 |
10 | 31313422535047 |
11 | 9a82a47755514 |
12 | 3618901a24807 |
13 | 1461ac6309c03 |
14 | 7a381344da99 |
15 | 3948022b6767 |
hex | 1c7ab96d4987 |
31313422535047 has 2 divisors, whose sum is σ = 31313422535048. Its totient is φ = 31313422535046.
The previous prime is 31313422535011. The next prime is 31313422535141. The reversal of 31313422535047 is 74053522431313.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31313422535047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31313422534994 and 31313422535012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31313422535147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15656711267523 + 15656711267524.
It is an arithmetic number, because the mean of its divisors is an integer number (15656711267524).
Almost surely, 231313422535047 is an apocalyptic number.
31313422535047 is a deficient number, since it is larger than the sum of its proper divisors (1).
31313422535047 is an equidigital number, since it uses as much as digits as its factorization.
31313422535047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 907200, while the sum is 43.
The spelling of 31313422535047 in words is "thirty-one trillion, three hundred thirteen billion, four hundred twenty-two million, five hundred thirty-five thousand, forty-seven".
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