Base | Representation |
---|---|
bin | 1001000111010010001… |
… | …10000111101011111111 |
3 | 1002221021211211221210101 |
4 | 10203221012013223333 |
5 | 20112311433402431 |
6 | 355505223421531 |
7 | 31424051660113 |
oct | 4435106075377 |
9 | 1087254757711 |
10 | 313148340991 |
11 | 110895090512 |
12 | 508348b48a7 |
13 | 236b6b6b335 |
14 | 11229483743 |
15 | 822bb63961 |
hex | 48e9187aff |
313148340991 has 2 divisors, whose sum is σ = 313148340992. Its totient is φ = 313148340990.
The previous prime is 313148340961. The next prime is 313148341013. The reversal of 313148340991 is 199043841313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313148340991 - 25 = 313148340959 is a prime.
It is a super-2 number, since 2×3131483409912 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313148340961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156574170495 + 156574170496.
It is an arithmetic number, because the mean of its divisors is an integer number (156574170496).
Almost surely, 2313148340991 is an apocalyptic number.
313148340991 is a deficient number, since it is larger than the sum of its proper divisors (1).
313148340991 is an equidigital number, since it uses as much as digits as its factorization.
313148340991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 279936, while the sum is 46.
The spelling of 313148340991 in words is "three hundred thirteen billion, one hundred forty-eight million, three hundred forty thousand, nine hundred ninety-one".
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