Base | Representation |
---|---|
bin | 100011100110110101101011… |
… | …0111011010011111100001111 |
3 | 1112001221202001220111120021112 |
4 | 1013031223112323103330033 |
5 | 312022442040011000221 |
6 | 3030042352223322235 |
7 | 122654016661010141 |
oct | 10715532673237417 |
9 | 1461852056446245 |
10 | 313201211031311 |
11 | 90882984541139 |
12 | 2b1645aba5037b |
13 | 1059b994266975 |
14 | 574b03b700c91 |
15 | 263213793415b |
hex | 11cdad6ed3f0f |
313201211031311 has 2 divisors, whose sum is σ = 313201211031312. Its totient is φ = 313201211031310.
The previous prime is 313201211031281. The next prime is 313201211031353. The reversal of 313201211031311 is 113130112102313.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313201211031311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313201216031311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156600605515655 + 156600605515656.
It is an arithmetic number, because the mean of its divisors is an integer number (156600605515656).
Almost surely, 2313201211031311 is an apocalyptic number.
313201211031311 is a deficient number, since it is larger than the sum of its proper divisors (1).
313201211031311 is an equidigital number, since it uses as much as digits as its factorization.
313201211031311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 313201211031311 its reverse (113130112102313), we get a palindrome (426331323133624).
The spelling of 313201211031311 in words is "three hundred thirteen trillion, two hundred one billion, two hundred eleven million, thirty-one thousand, three hundred eleven".
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