Base | Representation |
---|---|
bin | 101101100100111111110… |
… | …101011001101010010011 |
3 | 102002102111120201101112011 |
4 | 231210333311121222103 |
5 | 402304021120402011 |
6 | 10354511242243351 |
7 | 442200260524303 |
oct | 55447765315223 |
9 | 12072446641464 |
10 | 3132102122131 |
11 | aa8353aa3324 |
12 | 4270327b6557 |
13 | 199482086488 |
14 | ab847641603 |
15 | 56716ddd621 |
hex | 2d93fd59a93 |
3132102122131 has 2 divisors, whose sum is σ = 3132102122132. Its totient is φ = 3132102122130.
The previous prime is 3132102122129. The next prime is 3132102122143. The reversal of 3132102122131 is 1312212012313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3132102122131 - 21 = 3132102122129 is a prime.
It is a super-2 number, since 2×31321021221312 (a number of 26 digits) contains 22 as substring.
Together with 3132102122129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3132102122231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1566051061065 + 1566051061066.
It is an arithmetic number, because the mean of its divisors is an integer number (1566051061066).
Almost surely, 23132102122131 is an apocalyptic number.
3132102122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3132102122131 is an equidigital number, since it uses as much as digits as its factorization.
3132102122131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 3132102122131 its reverse (1312212012313), we get a palindrome (4444314134444).
The spelling of 3132102122131 in words is "three trillion, one hundred thirty-two billion, one hundred two million, one hundred twenty-two thousand, one hundred thirty-one".
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