Base | Representation |
---|---|
bin | 100011100110111011101001… |
… | …1101011110101000111011100 |
3 | 1112001222222012002101002200001 |
4 | 1013031313103223311013130 |
5 | 312023144324113340012 |
6 | 3030052313321544044 |
7 | 122654652635400142 |
oct | 10715672353650734 |
9 | 1461888162332601 |
10 | 313214041543132 |
11 | 90888368a83614 |
12 | 2b166b90945024 |
13 | 1059cc5a4a52b2 |
14 | 574b8d774b592 |
15 | 2632639057357 |
hex | 11cddd3af51dc |
313214041543132 has 24 divisors (see below), whose sum is σ = 548490271202720. Its totient is φ = 156502569268800.
The previous prime is 313214041543111. The next prime is 313214041543153. The reversal of 313214041543132 is 231345140412313.
It is an interprime number because it is at equal distance from previous prime (313214041543111) and next prime (313214041543153).
It is a junction number, because it is equal to n+sod(n) for n = 313214041543091 and 313214041543100.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32892094 + ... + 41331802.
Almost surely, 2313214041543132 is an apocalyptic number.
It is an amenable number.
313214041543132 is a deficient number, since it is larger than the sum of its proper divisors (235276229659588).
313214041543132 is a wasteful number, since it uses less digits than its factorization.
313214041543132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8445901 (or 8445899 counting only the distinct ones).
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 313214041543132 its reverse (231345140412313), we get a palindrome (544559181955445).
The spelling of 313214041543132 in words is "three hundred thirteen trillion, two hundred fourteen billion, forty-one million, five hundred forty-three thousand, one hundred thirty-two".
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