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313233121332347 is a prime number
BaseRepresentation
bin100011100111000100100010…
…0111011011100110001111011
31112002001210102210100211000212
41013032021010323130301323
5312024002413030113342
63030105150500021335
7122656226515050566
oct10716110473346173
91462053383324025
10313233121332347
119089546a026657
122b16a81669184b
13105a19ab32b1b8
14574c7c77354dd
152632da4103182
hex11ce244edcc7b

313233121332347 has 2 divisors, whose sum is σ = 313233121332348. Its totient is φ = 313233121332346.

The previous prime is 313233121332247. The next prime is 313233121332349. The reversal of 313233121332347 is 743233121332313.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 313233121332347 - 222 = 313233117138043 is a prime.

It is a super-2 number, since 2×3132331213323472 (a number of 30 digits) contains 22 as substring.

Together with 313233121332349, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (313233121332349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156616560666173 + 156616560666174.

It is an arithmetic number, because the mean of its divisors is an integer number (156616560666174).

Almost surely, 2313233121332347 is an apocalyptic number.

313233121332347 is a deficient number, since it is larger than the sum of its proper divisors (1).

313233121332347 is an equidigital number, since it uses as much as digits as its factorization.

313233121332347 is an evil number, because the sum of its binary digits is even.

The product of its digits is 489888, while the sum is 41.

The spelling of 313233121332347 in words is "three hundred thirteen trillion, two hundred thirty-three billion, one hundred twenty-one million, three hundred thirty-two thousand, three hundred forty-seven".