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313244124113 is a prime number
BaseRepresentation
bin1001000111011101100…
…11100000001111010001
31002221112112002020112102
410203232303200033101
520113010443432423
6355522524410145
731426324060154
oct4435663401721
91087475066472
10313244124113
11110934161818
12508609a6955
132370096663b
1411238097c9b
158235283c28
hex48eece03d1

313244124113 has 2 divisors, whose sum is σ = 313244124114. Its totient is φ = 313244124112.

The previous prime is 313244124107. The next prime is 313244124119. The reversal of 313244124113 is 311421442313.

It is a balanced prime because it is at equal distance from previous prime (313244124107) and next prime (313244124119).

It can be written as a sum of positive squares in only one way, i.e., 202839442129 + 110404681984 = 450377^2 + 332272^2 .

It is a cyclic number.

It is not a de Polignac number, because 313244124113 - 26 = 313244124049 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (313244124119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156622062056 + 156622062057.

It is an arithmetic number, because the mean of its divisors is an integer number (156622062057).

Almost surely, 2313244124113 is an apocalyptic number.

It is an amenable number.

313244124113 is a deficient number, since it is larger than the sum of its proper divisors (1).

313244124113 is an equidigital number, since it uses as much as digits as its factorization.

313244124113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 29.

Adding to 313244124113 its reverse (311421442313), we get a palindrome (624665566426).

The spelling of 313244124113 in words is "three hundred thirteen billion, two hundred forty-four million, one hundred twenty-four thousand, one hundred thirteen".