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31325400436457 is a prime number
BaseRepresentation
bin1110001111101100000110…
…10111011000111011101001
311002220200100000110002002002
413013312003113120323221
513101213410002431312
6150342405034220345
76412120424252321
oct707660327307351
9132820300402062
1031325400436457
119a88033993096
12361b0a52846b5
131462c84a0503a
147a422c158281
15394ca3b1e4c2
hex1c7d835d8ee9

31325400436457 has 2 divisors, whose sum is σ = 31325400436458. Its totient is φ = 31325400436456.

The previous prime is 31325400436441. The next prime is 31325400436513. The reversal of 31325400436457 is 75463400452313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23154612581776 + 8170787854681 = 4811924^2 + 2858459^2 .

It is a cyclic number.

It is not a de Polignac number, because 31325400436457 - 24 = 31325400436441 is a prime.

It is not a weakly prime, because it can be changed into another prime (31325400439457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15662700218228 + 15662700218229.

It is an arithmetic number, because the mean of its divisors is an integer number (15662700218229).

Almost surely, 231325400436457 is an apocalyptic number.

It is an amenable number.

31325400436457 is a deficient number, since it is larger than the sum of its proper divisors (1).

31325400436457 is an equidigital number, since it uses as much as digits as its factorization.

31325400436457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3628800, while the sum is 47.

The spelling of 31325400436457 in words is "thirty-one trillion, three hundred twenty-five billion, four hundred million, four hundred thirty-six thousand, four hundred fifty-seven".