Base | Representation |
---|---|
bin | 101101100101110101100… |
… | …010110111011101100001 |
3 | 102002111211101022120102021 |
4 | 231211311202313131201 |
5 | 402312342311424441 |
6 | 10355140512221441 |
7 | 442231512041116 |
oct | 55456542673541 |
9 | 12074741276367 |
10 | 3133003233121 |
11 | aa8776714353 |
12 | 42724453a881 |
13 | 19959697b748 |
14 | ab8d11aa90d |
15 | 5676b0893d1 |
hex | 2d9758b7761 |
3133003233121 has 2 divisors, whose sum is σ = 3133003233122. Its totient is φ = 3133003233120.
The previous prime is 3133003233103. The next prime is 3133003233167. The reversal of 3133003233121 is 1213323003313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2767781232225 + 365222000896 = 1663665^2 + 604336^2 .
It is a cyclic number.
It is not a de Polignac number, because 3133003233121 - 25 = 3133003233089 is a prime.
It is not a weakly prime, because it can be changed into another prime (3133003233721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1566501616560 + 1566501616561.
It is an arithmetic number, because the mean of its divisors is an integer number (1566501616561).
Almost surely, 23133003233121 is an apocalyptic number.
It is an amenable number.
3133003233121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3133003233121 is an equidigital number, since it uses as much as digits as its factorization.
3133003233121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 3133003233121 its reverse (1213323003313), we get a palindrome (4346326236434).
The spelling of 3133003233121 in words is "three trillion, one hundred thirty-three billion, three million, two hundred thirty-three thousand, one hundred twenty-one".
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