Base | Representation |
---|---|
bin | 101101100101110111010… |
… | …100110011001110110101 |
3 | 102002111220110111222100212 |
4 | 231211313110303032311 |
5 | 402312422433201323 |
6 | 10355143500315205 |
7 | 442232323644152 |
oct | 55456724631665 |
9 | 12074813458325 |
10 | 3133033100213 |
11 | aa87915639a5 |
12 | 427252542b05 |
13 | 19959cc08093 |
14 | ab8d5143229 |
15 | 5676d9d8b78 |
hex | 2d9775333b5 |
3133033100213 has 2 divisors, whose sum is σ = 3133033100214. Its totient is φ = 3133033100212.
The previous prime is 3133033100191. The next prime is 3133033100233. The reversal of 3133033100213 is 3120013303313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2732088327409 + 400944772804 = 1652903^2 + 633202^2 .
It is a cyclic number.
It is not a de Polignac number, because 3133033100213 - 28 = 3133033099957 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3133033100233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1566516550106 + 1566516550107.
It is an arithmetic number, because the mean of its divisors is an integer number (1566516550107).
Almost surely, 23133033100213 is an apocalyptic number.
It is an amenable number.
3133033100213 is a deficient number, since it is larger than the sum of its proper divisors (1).
3133033100213 is an equidigital number, since it uses as much as digits as its factorization.
3133033100213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 3133033100213 its reverse (3120013303313), we get a palindrome (6253046403526).
The spelling of 3133033100213 in words is "three trillion, one hundred thirty-three billion, thirty-three million, one hundred thousand, two hundred thirteen".
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