Base | Representation |
---|---|
bin | 1001000111100101110… |
… | …10101011001001110001 |
3 | 1002221201022220020001212 |
4 | 10203302322223021301 |
5 | 20113131124101224 |
6 | 355533431205505 |
7 | 31431122342063 |
oct | 4436272531161 |
9 | 1087638806055 |
10 | 313313112689 |
11 | 11096a0a1975 |
12 | 5087bb16895 |
13 | 2371203c995 |
14 | 112432d5733 |
15 | 823b35ed0e |
hex | 48f2eab271 |
313313112689 has 2 divisors, whose sum is σ = 313313112690. Its totient is φ = 313313112688.
The previous prime is 313313112661. The next prime is 313313112691. The reversal of 313313112689 is 986211313313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 162840496225 + 150472616464 = 403535^2 + 387908^2 .
It is a cyclic number.
It is not a de Polignac number, because 313313112689 - 212 = 313313108593 is a prime.
Together with 313313112691, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (313313142689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156656556344 + 156656556345.
It is an arithmetic number, because the mean of its divisors is an integer number (156656556345).
Almost surely, 2313313112689 is an apocalyptic number.
It is an amenable number.
313313112689 is a deficient number, since it is larger than the sum of its proper divisors (1).
313313112689 is an equidigital number, since it uses as much as digits as its factorization.
313313112689 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69984, while the sum is 41.
The spelling of 313313112689 in words is "three hundred thirteen billion, three hundred thirteen million, one hundred twelve thousand, six hundred eighty-nine".
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