Base | Representation |
---|---|
bin | 100011100111101001110011… |
… | …1010100000101110010110111 |
3 | 1112002100110000111001002011111 |
4 | 1013033103213110011302313 |
5 | 312031310320202041434 |
6 | 3030210024301415451 |
7 | 122665062030002521 |
oct | 10717234724056267 |
9 | 1462313014032144 |
10 | 313313155112119 |
11 | 909163aa0049a8 |
12 | 2b18223186a587 |
13 | 105a93c445c536 |
14 | 575261ab84a11 |
15 | 2634eda545964 |
hex | 11cf4e7505cb7 |
313313155112119 has 2 divisors, whose sum is σ = 313313155112120. Its totient is φ = 313313155112118.
The previous prime is 313313155112071. The next prime is 313313155112137. The reversal of 313313155112119 is 911211551313313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313313155112119 - 237 = 313175716158647 is a prime.
It is a super-2 number, since 2×3133131551121192 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313313155112149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156656577556059 + 156656577556060.
It is an arithmetic number, because the mean of its divisors is an integer number (156656577556060).
Almost surely, 2313313155112119 is an apocalyptic number.
313313155112119 is a deficient number, since it is larger than the sum of its proper divisors (1).
313313155112119 is an equidigital number, since it uses as much as digits as its factorization.
313313155112119 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 36450, while the sum is 40.
The spelling of 313313155112119 in words is "three hundred thirteen trillion, three hundred thirteen billion, one hundred fifty-five million, one hundred twelve thousand, one hundred nineteen".
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