Base | Representation |
---|---|
bin | 1001000111101010001… |
… | …01100110110111010101 |
3 | 1002221210212102120112111 |
4 | 10203311011212313111 |
5 | 20113214440030031 |
6 | 355541211551021 |
7 | 31432044041131 |
oct | 4436505466725 |
9 | 1087725376474 |
10 | 313349533141 |
11 | 110988708117 |
12 | 5089015b471 |
13 | 23719752148 |
14 | 112480963c1 |
15 | 823e6561b1 |
hex | 48f5166dd5 |
313349533141 has 2 divisors, whose sum is σ = 313349533142. Its totient is φ = 313349533140.
The previous prime is 313349533097. The next prime is 313349533153. The reversal of 313349533141 is 141335943313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 199996784100 + 113352749041 = 447210^2 + 336679^2 .
It is a cyclic number.
It is not a de Polignac number, because 313349533141 - 211 = 313349531093 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 313349533094 and 313349533103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313349533171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156674766570 + 156674766571.
It is an arithmetic number, because the mean of its divisors is an integer number (156674766571).
Almost surely, 2313349533141 is an apocalyptic number.
It is an amenable number.
313349533141 is a deficient number, since it is larger than the sum of its proper divisors (1).
313349533141 is an equidigital number, since it uses as much as digits as its factorization.
313349533141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 174960, while the sum is 40.
The spelling of 313349533141 in words is "three hundred thirteen billion, three hundred forty-nine million, five hundred thirty-three thousand, one hundred forty-one".
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