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313352874397 is a prime number
BaseRepresentation
bin1001000111101010100…
…10010110100110011101
31002221211002201022212201
410203311102112212131
520113221313440042
6355541411331501
731432114325323
oct4436522264635
91087732638781
10313352874397
1111098a58a492
12508912b0b91
132371a351c14
14112486c5d13
15823eab61b7
hex48f549699d

313352874397 has 2 divisors, whose sum is σ = 313352874398. Its totient is φ = 313352874396.

The previous prime is 313352874379. The next prime is 313352874413. The reversal of 313352874397 is 793478253313.

Together with previous prime (313352874379) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 313164471321 + 188403076 = 559611^2 + 13726^2 .

It is a cyclic number.

It is not a de Polignac number, because 313352874397 - 27 = 313352874269 is a prime.

It is a super-2 number, since 2×3133528743972 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313352874337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156676437198 + 156676437199.

It is an arithmetic number, because the mean of its divisors is an integer number (156676437199).

Almost surely, 2313352874397 is an apocalyptic number.

It is an amenable number.

313352874397 is a deficient number, since it is larger than the sum of its proper divisors (1).

313352874397 is an equidigital number, since it uses as much as digits as its factorization.

313352874397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11430720, while the sum is 55.

The spelling of 313352874397 in words is "three hundred thirteen billion, three hundred fifty-two million, eight hundred seventy-four thousand, three hundred ninety-seven".