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31341213340000 = 25543771837187
BaseRepresentation
bin1110010000001001100011…
…11000110101000101100000
311002222012011001012210210021
413020010301320311011200
513101443301103340000
6150353542111443224
76413220324600034
oct710046170650540
9132865131183707
1031341213340000
119a93808959613
123622178b26514
131464604aa12b5
147a4ccc3061c4
153953cbea911a
hex1c8131e35160

31341213340000 has 480 divisors, whose sum is σ = 81282121595136. Its totient is φ = 11879320320000.

The previous prime is 31341213339983. The next prime is 31341213340051. The reversal of 31341213340000 is 4331214313.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 4360816407 + ... + 4360823593.

Almost surely, 231341213340000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31341213340000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (40641060797568).

31341213340000 is an abundant number, since it is smaller than the sum of its proper divisors (49940908255136).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31341213340000 is an equidigital number, since it uses as much as digits as its factorization.

31341213340000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7408 (or 7385 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 31341213340000 its reverse (4331214313), we get a palindrome (31345544554313).

The spelling of 31341213340000 in words is "thirty-one trillion, three hundred forty-one billion, two hundred thirteen million, three hundred forty thousand".