Base | Representation |
---|---|
bin | 100011101000011000011100… |
… | …1110011011101010001111111 |
3 | 1112002201000120101011222102201 |
4 | 1013100300321303131101333 |
5 | 312034430441232024203 |
6 | 3030324032033532331 |
7 | 123005236215451432 |
oct | 10720607163352177 |
9 | 1462630511158381 |
10 | 313413323314303 |
11 | 90954931384873 |
12 | 2b199727a140a7 |
13 | 105b5998a71ba4 |
14 | 57574002ab819 |
15 | 26378ee407e1d |
hex | 11d0c39cdd47f |
313413323314303 has 2 divisors, whose sum is σ = 313413323314304. Its totient is φ = 313413323314302.
The previous prime is 313413323314291. The next prime is 313413323314321. The reversal of 313413323314303 is 303413323314313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313413323314303 - 229 = 313412786443391 is a prime.
It is a super-2 number, since 2×3134133233143032 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313413323314703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156706661657151 + 156706661657152.
It is an arithmetic number, because the mean of its divisors is an integer number (156706661657152).
Almost surely, 2313413323314303 is an apocalyptic number.
313413323314303 is a deficient number, since it is larger than the sum of its proper divisors (1).
313413323314303 is an equidigital number, since it uses as much as digits as its factorization.
313413323314303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 209952, while the sum is 37.
Adding to 313413323314303 its reverse (303413323314313), we get a palindrome (616826646628616).
The spelling of 313413323314303 in words is "three hundred thirteen trillion, four hundred thirteen billion, three hundred twenty-three million, three hundred fourteen thousand, three hundred three".
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