Base | Representation |
---|---|
bin | 101101100111001110111… |
… | …000011010110111100011 |
3 | 102002122200211121122001100 |
4 | 231213032320122313203 |
5 | 402323430011233040 |
6 | 10355545333205443 |
7 | 442313611602264 |
oct | 55471670326743 |
9 | 12078624548040 |
10 | 3134502055395 |
11 | aa937576a747 |
12 | 4275a2490883 |
13 | 19977534a929 |
14 | ab9d428496b |
15 | 5680794eb30 |
hex | 2d9cee1ade3 |
3134502055395 has 96 divisors (see below), whose sum is σ = 5564559933504. Its totient is φ = 1631641190400.
The previous prime is 3134502055351. The next prime is 3134502055441. The reversal of 3134502055395 is 5935502054313.
3134502055395 is a `hidden beast` number, since 3 + 1 + 3 + 4 + 5 + 0 + 2 + 0 + 553 + 95 = 666.
3134502055395 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3134502055395 - 213 = 3134502047203 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a self number, because there is not a number n which added to its sum of digits gives 3134502055395.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 673070907 + ... + 673075563.
It is an arithmetic number, because the mean of its divisors is an integer number (57964165974).
Almost surely, 23134502055395 is an apocalyptic number.
3134502055395 is a deficient number, since it is larger than the sum of its proper divisors (2430057878109).
3134502055395 is a wasteful number, since it uses less digits than its factorization.
3134502055395 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6133 (or 6130 counting only the distinct ones).
The product of its (nonzero) digits is 1215000, while the sum is 45.
The spelling of 3134502055395 in words is "three trillion, one hundred thirty-four billion, five hundred two million, fifty-five thousand, three hundred ninety-five".
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