Base | Representation |
---|---|
bin | 101101100111010001001… |
… | …001100011100101011101 |
3 | 102002122210111012121011011 |
4 | 231213101021203211131 |
5 | 402324014231230411 |
6 | 10355553212455221 |
7 | 442314553153261 |
oct | 55472111434535 |
9 | 12078714177134 |
10 | 3134540101981 |
11 | aa9395196702 |
12 | 4275b317a511 |
13 | 1997801ac2c2 |
14 | ab9d934a0a1 |
15 | 5680ae67c21 |
hex | 2d9d126395d |
3134540101981 has 2 divisors, whose sum is σ = 3134540101982. Its totient is φ = 3134540101980.
The previous prime is 3134540101933. The next prime is 3134540101993. The reversal of 3134540101981 is 1891010454313.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3009270825625 + 125269276356 = 1734725^2 + 353934^2 .
It is an emirp because it is prime and its reverse (1891010454313) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3134540101981 is a prime.
It is a super-2 number, since 2×31345401019812 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3134540101921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567270050990 + 1567270050991.
It is an arithmetic number, because the mean of its divisors is an integer number (1567270050991).
Almost surely, 23134540101981 is an apocalyptic number.
It is an amenable number.
3134540101981 is a deficient number, since it is larger than the sum of its proper divisors (1).
3134540101981 is an equidigital number, since it uses as much as digits as its factorization.
3134540101981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 40.
The spelling of 3134540101981 in words is "three trillion, one hundred thirty-four billion, five hundred forty million, one hundred one thousand, nine hundred eighty-one".
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