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3134540101981 is a prime number
BaseRepresentation
bin101101100111010001001…
…001100011100101011101
3102002122210111012121011011
4231213101021203211131
5402324014231230411
610355553212455221
7442314553153261
oct55472111434535
912078714177134
103134540101981
11aa9395196702
124275b317a511
131997801ac2c2
14ab9d934a0a1
155680ae67c21
hex2d9d126395d

3134540101981 has 2 divisors, whose sum is σ = 3134540101982. Its totient is φ = 3134540101980.

The previous prime is 3134540101933. The next prime is 3134540101993. The reversal of 3134540101981 is 1891010454313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3009270825625 + 125269276356 = 1734725^2 + 353934^2 .

It is an emirp because it is prime and its reverse (1891010454313) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3134540101981 is a prime.

It is a super-2 number, since 2×31345401019812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3134540101921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567270050990 + 1567270050991.

It is an arithmetic number, because the mean of its divisors is an integer number (1567270050991).

Almost surely, 23134540101981 is an apocalyptic number.

It is an amenable number.

3134540101981 is a deficient number, since it is larger than the sum of its proper divisors (1).

3134540101981 is an equidigital number, since it uses as much as digits as its factorization.

3134540101981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 40.

The spelling of 3134540101981 in words is "three trillion, one hundred thirty-four billion, five hundred forty million, one hundred one thousand, nine hundred eighty-one".