Base | Representation |
---|---|
bin | 101101100111011100001… |
… | …000111111011000010111 |
3 | 102002200021100012010212212 |
4 | 231213130020333120113 |
5 | 402324403433044223 |
6 | 10400023401104035 |
7 | 442322252431616 |
oct | 55473410773027 |
9 | 12080240163785 |
10 | 3134724503063 |
11 | aa947a29499a |
12 | 427644a8801b |
13 | 1997ac46447a |
14 | aba15a2b87d |
15 | 5681c240278 |
hex | 2d9dc23f617 |
3134724503063 has 2 divisors, whose sum is σ = 3134724503064. Its totient is φ = 3134724503062.
The previous prime is 3134724503023. The next prime is 3134724503087. The reversal of 3134724503063 is 3603054274313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3134724503063 - 212 = 3134724498967 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3134724503063.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3134724503003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567362251531 + 1567362251532.
It is an arithmetic number, because the mean of its divisors is an integer number (1567362251532).
Almost surely, 23134724503063 is an apocalyptic number.
3134724503063 is a deficient number, since it is larger than the sum of its proper divisors (1).
3134724503063 is an equidigital number, since it uses as much as digits as its factorization.
3134724503063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 41.
Adding to 3134724503063 its reverse (3603054274313), we get a palindrome (6737778777376).
The spelling of 3134724503063 in words is "three trillion, one hundred thirty-four billion, seven hundred twenty-four million, five hundred three thousand, sixty-three".
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