Base | Representation |
---|---|
bin | 101101101000000000011… |
… | …110101010011110110001 |
3 | 102002201211211101011000102 |
4 | 231220000132222132301 |
5 | 402332131021230101 |
6 | 10400204100202145 |
7 | 442343334450125 |
oct | 55500036523661 |
9 | 12081754334012 |
10 | 3135334164401 |
11 | aa976244153a |
12 | 427795099355 |
13 | 19987886371a |
14 | aba729ab585 |
15 | 56855a1a86b |
hex | 2da007aa7b1 |
3135334164401 has 2 divisors, whose sum is σ = 3135334164402. Its totient is φ = 3135334164400.
The previous prime is 3135334164383. The next prime is 3135334164461. The reversal of 3135334164401 is 1044614335313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2924616442801 + 210717721600 = 1710151^2 + 459040^2 .
It is a cyclic number.
It is not a de Polignac number, because 3135334164401 - 226 = 3135267055537 is a prime.
It is not a weakly prime, because it can be changed into another prime (3135334164461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567667082200 + 1567667082201.
It is an arithmetic number, because the mean of its divisors is an integer number (1567667082201).
Almost surely, 23135334164401 is an apocalyptic number.
It is an amenable number.
3135334164401 is a deficient number, since it is larger than the sum of its proper divisors (1).
3135334164401 is an equidigital number, since it uses as much as digits as its factorization.
3135334164401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 38.
Adding to 3135334164401 its reverse (1044614335313), we get a palindrome (4179948499714).
The spelling of 3135334164401 in words is "three trillion, one hundred thirty-five billion, three hundred thirty-four million, one hundred sixty-four thousand, four hundred one".
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