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3135442001 is a prime number
BaseRepresentation
bin1011101011100011…
…0000110001010001
322002111212221211112
42322320300301101
522410133121001
61235043223105
7140461550216
oct27270606121
98074787745
103135442001
111369969a8a
12736077a95
133ac787033
1421a5c1b0d
151353e9cbb
hexbae30c51

3135442001 has 2 divisors, whose sum is σ = 3135442002. Its totient is φ = 3135442000.

The previous prime is 3135441989. The next prime is 3135442003. The reversal of 3135442001 is 1002445313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2313129025 + 822312976 = 48095^2 + 28676^2 .

It is an emirp because it is prime and its reverse (1002445313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3135442001 - 218 = 3135179857 is a prime.

Together with 3135442003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3135442003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567721000 + 1567721001.

It is an arithmetic number, because the mean of its divisors is an integer number (1567721001).

Almost surely, 23135442001 is an apocalyptic number.

It is an amenable number.

3135442001 is a deficient number, since it is larger than the sum of its proper divisors (1).

3135442001 is an equidigital number, since it uses as much as digits as its factorization.

3135442001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 3135442001 is about 55995.0176444298. The cubic root of 3135442001 is about 1463.6354638542.

Adding to 3135442001 its reverse (1002445313), we get a palindrome (4137887314).

The spelling of 3135442001 in words is "three billion, one hundred thirty-five million, four hundred forty-two thousand, one".