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3135451212433 is a prime number
BaseRepresentation
bin101101101000000111011…
…101001010101010010001
3102002202010222121210201201
4231220013131022222101
5402332401002244213
610400223441031201
7442346255365051
oct55500735125221
912082128553651
103135451212433
11aa9812517451
12427808325501
13199896b95b07
14aba84359561
1556860e3b6dd
hex2da0774aa91

3135451212433 has 2 divisors, whose sum is σ = 3135451212434. Its totient is φ = 3135451212432.

The previous prime is 3135451212419. The next prime is 3135451212461. The reversal of 3135451212433 is 3342121545313.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2470014570384 + 665436642049 = 1571628^2 + 815743^2 .

It is an emirp because it is prime and its reverse (3342121545313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3135451212433 - 25 = 3135451212401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3135451212392 and 3135451212401.

It is not a weakly prime, because it can be changed into another prime (3135451212403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1567725606216 + 1567725606217.

It is an arithmetic number, because the mean of its divisors is an integer number (1567725606217).

Almost surely, 23135451212433 is an apocalyptic number.

It is an amenable number.

3135451212433 is a deficient number, since it is larger than the sum of its proper divisors (1).

3135451212433 is an equidigital number, since it uses as much as digits as its factorization.

3135451212433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 129600, while the sum is 37.

Adding to 3135451212433 its reverse (3342121545313), we get a palindrome (6477572757746).

The spelling of 3135451212433 in words is "three trillion, one hundred thirty-five billion, four hundred fifty-one million, two hundred twelve thousand, four hundred thirty-three".