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313716334474117 is a prime number
BaseRepresentation
bin100011101010100101100011…
…0101011010011001110000101
31112010202222200202010202220101
41013111023012223103032011
5312104412023111132432
63031115143334404101
7123036154136016511
oct10725130653231605
91463688622122811
10313716334474117
1190a61394273aa3
122b2283b1800631
1310608428691763
145767d472bd141
1526407361124e7
hex11d52c6ad3385

313716334474117 has 2 divisors, whose sum is σ = 313716334474118. Its totient is φ = 313716334474116.

The previous prime is 313716334474093. The next prime is 313716334474241. The reversal of 313716334474117 is 711474433617313.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 313699676441761 + 16658032356 = 17711569^2 + 129066^2 .

It is an emirp because it is prime and its reverse (711474433617313) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 313716334474117 - 223 = 313716326085509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313716338474117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156858167237058 + 156858167237059.

It is an arithmetic number, because the mean of its divisors is an integer number (156858167237059).

Almost surely, 2313716334474117 is an apocalyptic number.

It is an amenable number.

313716334474117 is a deficient number, since it is larger than the sum of its proper divisors (1).

313716334474117 is an equidigital number, since it uses as much as digits as its factorization.

313716334474117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10668672, while the sum is 55.

The spelling of 313716334474117 in words is "three hundred thirteen trillion, seven hundred sixteen billion, three hundred thirty-four million, four hundred seventy-four thousand, one hundred seventeen".