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3140004103 is a prime number
BaseRepresentation
bin1011101100101000…
…1010100100000111
322002211110201212021
42323022022210013
522412320112403
61235325104011
7140545410625
oct27312124407
98084421767
103140004103
1113714a5615
127376b8007
133b06c36c2
1421b04c515
151359eb8bd
hexbb28a907

3140004103 has 2 divisors, whose sum is σ = 3140004104. Its totient is φ = 3140004102.

The previous prime is 3140004037. The next prime is 3140004113. The reversal of 3140004103 is 3014000413.

It is a strong prime.

It is an emirp because it is prime and its reverse (3014000413) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3140004103 - 229 = 2603133191 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3140004113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570002051 + 1570002052.

It is an arithmetic number, because the mean of its divisors is an integer number (1570002052).

Almost surely, 23140004103 is an apocalyptic number.

3140004103 is a deficient number, since it is larger than the sum of its proper divisors (1).

3140004103 is an equidigital number, since it uses as much as digits as its factorization.

3140004103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 16.

The square root of 3140004103 is about 56035.7395150631. The cubic root of 3140004103 is about 1464.3449883165.

Adding to 3140004103 its reverse (3014000413), we get a palindrome (6154004516).

It can be divided in two parts, 314000410 and 3, that added together give a palindrome (314000413).

The spelling of 3140004103 in words is "three billion, one hundred forty million, four thousand, one hundred three".