Base | Representation |
---|---|
bin | 1110010001110111010001… |
… | …00001110001001100110111 |
3 | 11010011211011210121211110102 |
4 | 13020323220201301030313 |
5 | 13103424412144201101 |
6 | 150441002400344315 |
7 | 6420404023025654 |
oct | 710735041611467 |
9 | 133154153554412 |
10 | 31400112100151 |
11 | a0067927548a3 |
12 | 363167601509b |
13 | 146a030335372 |
14 | 7a7ab8816c2b |
15 | 396bc7bcd86b |
hex | 1c8ee8871337 |
31400112100151 has 2 divisors, whose sum is σ = 31400112100152. Its totient is φ = 31400112100150.
The previous prime is 31400112100139. The next prime is 31400112100207. The reversal of 31400112100151 is 15100121100413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31400112100151 - 230 = 31399038358327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31400112130151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700056050075 + 15700056050076.
It is an arithmetic number, because the mean of its divisors is an integer number (15700056050076).
Almost surely, 231400112100151 is an apocalyptic number.
31400112100151 is a deficient number, since it is larger than the sum of its proper divisors (1).
31400112100151 is an equidigital number, since it uses as much as digits as its factorization.
31400112100151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 31400112100151 its reverse (15100121100413), we get a palindrome (46500233200564).
The spelling of 31400112100151 in words is "thirty-one trillion, four hundred billion, one hundred twelve million, one hundred thousand, one hundred fifty-one".
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