3140045113 has 2 divisors, whose sum is σ = 3140045114. Its totient is φ = 3140045112.

The previous prime is 3140045107. The next prime is 3140045119. The reversal of 3140045113 is 3115400413.

3140045113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (3140045107) and next prime (3140045119).

It can be written as a sum of positive squares in only one way, i.e., 2881864489 + 258180624 = 53683^2 + 16068^2 .

It is a cyclic number.

It is not a de Polignac number, because 3140045113 - 2⁵ = 3140045081 is a prime.

It is not a weakly prime, because it can be changed into another prime (3140045119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570022556 + 1570022557.

It is an arithmetic number, because the mean of its divisors is an integer number (1570022557).

Almost surely, 2^3140045113 is an apocalyptic number.

It is an amenable number.

3140045113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3140045113 is an equidigital number, since it uses as much as digits as its factorization.

3140045113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 3140045113 is about 56036.1054410458. The cubic root of 3140045113 is about 1464.3513633110.

Adding to 3140045113 its reverse (3115400413), we get a palindrome (6255445526).

The spelling of 3140045113 in words is "three billion, one hundred forty million, forty-five thousand, one hundred thirteen".