Base | Representation |
---|---|
bin | 10010101101110… |
… | …101010111100001 |
3 | 210212212002211101 |
4 | 102231311113201 |
5 | 1120341124321 |
6 | 51054114401 |
7 | 10531666234 |
oct | 2255652741 |
9 | 725762741 |
10 | 314004961 |
11 | 15127a636 |
12 | 891aba01 |
13 | 5009256a |
14 | 2d9bb41b |
15 | 1c878791 |
hex | 12b755e1 |
314004961 has 2 divisors, whose sum is σ = 314004962. Its totient is φ = 314004960.
The previous prime is 314004949. The next prime is 314004973. The reversal of 314004961 is 169400413.
It is a balanced prime because it is at equal distance from previous prime (314004949) and next prime (314004973).
It can be written as a sum of positive squares in only one way, i.e., 313998400 + 6561 = 17720^2 + 81^2 .
It is a cyclic number.
It is not a de Polignac number, because 314004961 - 213 = 313996769 is a prime.
It is a super-2 number, since 2×3140049612 = 197198231065223042, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (314004931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157002480 + 157002481.
It is an arithmetic number, because the mean of its divisors is an integer number (157002481).
Almost surely, 2314004961 is an apocalyptic number.
It is an amenable number.
314004961 is a deficient number, since it is larger than the sum of its proper divisors (1).
314004961 is an equidigital number, since it uses as much as digits as its factorization.
314004961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
The square root of 314004961 is about 17720.1851288298. The cubic root of 314004961 is about 679.6920181152.
The spelling of 314004961 in words is "three hundred fourteen million, four thousand, nine hundred sixty-one".
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