Base | Representation |
---|---|
bin | 1110010001111001001011… |
… | …10100011011010000110111 |
3 | 11010011220211110112221022201 |
4 | 13020330211310123100313 |
5 | 13103434013420314312 |
6 | 150441252412405331 |
7 | 6420441350321143 |
oct | 710744564332067 |
9 | 133156743487281 |
10 | 31401140401207 |
11 | a007170148685 |
12 | 3631902476847 |
13 | 146a1653a1125 |
14 | 7a7b75210223 |
15 | 396c38100557 |
hex | 1c8f25d1b437 |
31401140401207 has 2 divisors, whose sum is σ = 31401140401208. Its totient is φ = 31401140401206.
The previous prime is 31401140401187. The next prime is 31401140401219. The reversal of 31401140401207 is 70210404110413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31401140401207 - 223 = 31401132012599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31401140401277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700570200603 + 15700570200604.
It is an arithmetic number, because the mean of its divisors is an integer number (15700570200604).
Almost surely, 231401140401207 is an apocalyptic number.
31401140401207 is a deficient number, since it is larger than the sum of its proper divisors (1).
31401140401207 is an equidigital number, since it uses as much as digits as its factorization.
31401140401207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
The spelling of 31401140401207 in words is "thirty-one trillion, four hundred one billion, one hundred forty million, four hundred one thousand, two hundred seven".
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